X – Xo = ½ (V – Vo)t ; has no acceleration variable

X – Xo = ½ (V – Vo)at2 ; has no velocity variable

V2 = V2o + 2a(X – Xo) ; has no time variable

Works only if there is uniform equation

V = Velocity

Vo = Final velocity

X = Initial position

Xo = Final position

A = acceleration

The below tells us, how much an object changes from here to there or form V0t to 1/2at2

∆x= V0t + 1/2at2

In real world, we have ‘g’ as gravity for ‘a’

g = 10m/s2 (meters per second square)

V = Vot + at => a = ∆x/∆t ; Final velocity less initial velocity is ∆x, divided by t

V2 = V2o + 2a∆x or v V2 = Vo2 + 2a(x-xo)

Here is a relationship between final velocity, initial velocity, acceleration and the distance travelled ∆x. x-xo is also

displacement or change in position.

Directional Derivatives** (Contd.)**

Source: Unknown